The Sum Of 3 Consecutive Integral Numbers Is 117. Find The Numbers.

Use the three steps to solve the problem. The sum of 3 consecutive integral numbers is 117. List your answers separated by a comma. Use the three steps to solve the problem.

So, 2 * n + 1 = 2 * 18 + 1 = 37. Now, we can get that 37 is the first integer of 3 consecutive odd integers whose sum is 117. So, the second odd integer is 39, the third odd integer is 41. The answer came out, the sum of 3 consecutive odd integers is 117, these three odd integers are 37, 39 and 41. 37 + 39 + 41 = 117. The sum of 3 consecutive integral numbers is 117 find the numbers? See answer (1) best answer. The sum of 3 consecutive integrals numbers is 117 find the numbers.

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